6x^2+24x-990=0

Solution for 6x^2+24x-990=0 equation:

6x^2+24x-990=0

a = 6; b = 24; c = -990;
Δ = b2-4ac
Δ = 242-4·6·(-990)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-156}{2*6}=\frac{-180}{12}
=-15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+156}{2*6}=\frac{132}{12}
=11
$